A die is thrown three times. Find `P(A//B)` and `P(B//A)` , if `A=4` appears on the third toss, B=6 and 5 appear respectively on first two tosses.

Explanation

It is known that if a die is thrown three times, then the number of elements in the sample space `S` will be,

`n(S)=6×6×6`

`=>n(S)=216`

It is given that `E` stands for "`4` appearing on the third toss", i.e.,

`E={(1,1,4),(1,2,4),...,(1,6,4),(2,1,4),(2,2,4),...,(2,6,4),(3,1,4),(3,2,4,),...,(3,6,4),(4,1,4),(4,2,4),...,(4,6,4),(5,1,4),(5,2,4),...,(5,6,4),(6,1,4),(6,2,4),...,(6,6,4)}`

Also, given that `F` stands for "`6` and `5` appearing on first two tosses", i.e.,

`F={(6,5,1),(6,5,2),(6,5,3),(6,5,4),(6,5,5),(6,5,6)}`

Here, `n(F)=6`

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