An electronic assembly consists of two sub-systems say A and B. From previous testing procedures, the following probabilities are assumed to be known. `P(Afa i l s)=0. 2 ,P(Bfa i l sa lon e)=0. 15 ,P(Aa n dF a i l)=0. 15.` Evaluate the following probabilities: `P(Afa i l s//Bh a sfa i l e d)` (ii) `P(Afa i l sa lon e)`

Explanation

Let the event in which A fails and B fails be denoted by A​ and B​
.

P(A​)=0.2


P(A​∩E​)=0.15

P(B fails alone)=`P(B​)−P(A​∩B)`


=`0.15=P(B​)−0.15`

...