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Find : (i) 9^(3/2) (ii) 32^(2/5) (iii) ...

Find : (i) `9^(3/2)` (ii) `32^(2/5)` (iii) `16^(3/4)` (iv) `125^((-1)/3)`

Text Solution

Verified by Experts

Here, we will use `(a^m)^n = a^(mn)`
(i) `9^3/2 = (3^2)^(3/2) = 3^3 = 27`

(ii)`32^(2/5) = (2^5)^(2/5) = 2^2 = 4`

(iii) `16^(3/4) = (2^4)^(3/4) = 2^3 = 8`

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