Represent `sqrt(6),sqrt(7),sqrt(8)` on the number line.

Explanation

as we can rewrite, `sqrt 7 = sqrt((2)^2 + sqrt(3)^2)`

and, `sqrt3 = sqrt((sqrt2)^2 + 1^2)`

draw a perpendicular at 1 unit

hypotenuse will be `sqrt2`

then circle will be drawn of radius `sqrt2`

now, 1 unit line is again drawn at point with hypotenuse of `sqrt3`

now, circle will be drawn of `sqrt3`

now draw perpendicular line of 2 units with hypotenuse `sqrt7`

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