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In Fig. 6.15, /P Q R=/P R Q, then prove ...

In Fig. 6.15, `/_P Q R=/_P R Q`, then prove that `/_P Q S=/_P R T`.

Text Solution

Verified by Experts

`anglePQS+anglePQR=180^o`-(1)
`anglePRQ+anglePRT=180^o`-(2)
`anglePQR=anglePRQ`(given)
`anglePQR+anglePRT=180^o`
`anglePQR=180^o-anglePRT`
putting this value in equation (1)
`anglePQS+180^o -anglePRT=180^o`
`anglePQS=anglePRT`
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