Home
Class 10
MATHS
Check whether 6^ncan end with the digit ...

Check whether `6^n`can end with the digit `0` for any natural number `n`.

Text Solution

Verified by Experts

We can write `6^n` as `(2**3)^n` or `2^n3^n`.
Now, for the end digit to be `0`, number should be divided by 10 or it should be divided by 2 and 5.
In our case, it can be divided by `2` and `3`, but, not by `5`.
So, given number can not end with 0.
Promotional Banner

Topper's Solved these Questions

  • REAL NUMBERS

    NCERT ENGLISH|Exercise Solved Examples|11 Videos
  • REAL NUMBERS

    NCERT ENGLISH|Exercise Exercise 1.4|3 Videos
  • REAL NUMBERS

    NCERT ENGLISH|Exercise EXERCISE 1.3|3 Videos
  • QUADRATIC EQUATIONS

    NCERT ENGLISH|Exercise All Questions|42 Videos
  • SOME APPLICATIONS OF TRIGONOMETRY

    NCERT ENGLISH|Exercise SOLVED EXAMPLES|7 Videos

Similar Questions

Explore conceptually related problems

Check whether 12^n can end with the digit 0 for any natural number n.

Check whether 12^n can end with the digit 0 for any natural number n .

Check whether 12^n can end with the digit 0 for any natural number n.

Check whether 6^(n) can end with the digit 0 (zero) for any natural number n .

Check whether 6^(n) can end with the digit '0' (zero) for any natural number n.

Show that 12^n cannot end with the digits 0 or 5 for any natural number n

Prove by mathematical induction that n^(5) and n have the same unit digit for any natural number n.

Check whether the relation R in the set N of natural numbers given by R = { (a,b) : a is a divisor of b } is reflexive, symmetric or transitive. Also determine whether R is an equivalence relation

check whether the relation R in the set N of natural numbers given by R = { (a,b) : a is divisor of b } is reflexive, symmetric or transitive. Also determine whether R is an equivalence relation

Write the negation of the following statements and check whether the resulting statements are true: Every natural number is greater than 0.