Find all the zeroes of `2x^4-3x^3-3x^2+6x-2`, if you know that two of its zeroes are `sqrt(2)`and `-sqrt(2)`.

Explanation

To find all the zeroes of the polynomial \(2x^4 - 3x^3 - 3x^2 + 6x - 2\), given that two of its zeroes are \(\sqrt{2}\) and \(-\sqrt{2}\), we can follow these steps:

### Step 1: Identify the factors from the known zeroes
Since \(\sqrt{2}\) and \(-\sqrt{2}\) are zeroes of the polynomial, we can express the polynomial as:
\[ P(x) = 2x^4 - 3x^3 - 3x^2 + 6x - 2 = (x - \sqrt{2})(x + \sqrt{2})Q(x) \]
where \(Q(x)\) is another polynomial.
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