Two water taps together can fill a tank in `9 3/8`hours. The tap of larger diameter takes 10 hours less than the smaller one to fill the tank separately. Find the time in which each tap can separately fill the tank.

Explanation

To solve the problem, we need to find the time taken by each tap to fill the tank separately. Let's denote the time taken by the smaller tap as \( x \) hours. Therefore, the time taken by the larger tap will be \( x - 10 \) hours.

### Step 1: Understand the rates of filling
The rate at which the smaller tap fills the tank is \( \frac{1}{x} \) tanks per hour, and the rate at which the larger tap fills the tank is \( \frac{1}{x - 10} \) tanks per hour.

### Step 2: Combined rate of both taps
According to the problem, both taps together can fill the tank in \( 9 \frac{3}{8} \) hours. We convert this mixed number into an improper fraction:
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