Find two consecutive odd positive integers, sum of whose squares is 290.

Options

A. `11, 13`
B. `12, 14`
C. `15, 18`
D. None of these

Explanation

let first odd positive integer be`x`

let the next integer be`x+2`

acc to question

`x^2 + (x+2)^2 = 290`

`x^2 + x^2 + 4 +4x=290`

`2x^2 + 4x -286=0`

`x^2 +2x-143=0`

`x^2 +13x-11x -143=0`

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