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Which term of the AP: 3, 15, 27, 39, . ....

Which term of the AP: 3, 15, 27, 39, . . . will be 132 more than its `54^(t h)`term?

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To solve the problem, we need to determine which term of the arithmetic progression (AP) 3, 15, 27, 39, ... is 132 more than its 54th term. ### Step-by-Step Solution: 1. **Identify the First Term (A) and Common Difference (D)**: - The first term \( A = 3 \). - The second term is \( 15 \), so the common difference \( D \) can be calculated as: \[ ...
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NCERT ENGLISH-ARITHMETIC PROGRESSIONS-All Questions
  1. How many three–digit numbers are divisible by 7?

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  2. Two APs have the same common difference. The difference between their...

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  3. Which term of the AP: 3, 15, 27, 39, . . . will be 132 more than its 5...

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  4. The 17^(th) term of an AP exceeds its 10^(th) term by 7. Find the comm...

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  5. Find the 20^(t h)term from the last term of the AP : 3, 8, 13, . . , ...

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  6. Determine the AP whose third term is 16 and the 7^(t h)term exceeds th...

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  7. For what value of n, are the nth terms of two APs: 63, 65, 67, . . . ...

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  8. How many multiples of 4 lie between 10 and 250?

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  9. In a potato race, a bucket is placed at the starting point, which is ...

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  10. Subba Rao started work in 1995 at an annual salary of Rs 5000 and rec...

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  11. The sum of the 4th and 8th terms of an AP is 24 and the sum of the 6t...

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  12. If the sum of first 7 terms of an AP is 49 and that of 17 terms is 28...

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  13. Find the sum of first 51 terms of an AP whose second and third terms ...

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  14. Find the 31^(s t) term of an AP whose 11^(t h)term is 38 and the 16^(t...

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  15. A ladder has rungs 25 cm apart, (see Figure). The rungs decrease unif...

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  16. In an AP: given a=8,an=62,Sn=210 find n and d

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  17. Find the sums given below : (i) 7+10 1/2+14+...+84 (ii) 34+32+30+...+...

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  18. Find the sum of the following APs : (i) 2, 7, 12, . . . , to 10 terms...

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  19. Find the sum of first 22 terms of an AP in which d=l and 22nd term is ...

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  20. The first and the last terms of an AP are 17 and 350 respectively. If...

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