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The 17^(th) term of an AP exceeds its 10...

The `17^(th)` term of an AP exceeds its `10^(th)` term by 7. Find the common difference.

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According to Question
`a_17=a_10+7`
`a_17-a_10=7`
(a+16d)-(a+9d)=7
a-a_16d-9d=7
7d=7
d=1
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NCERT ENGLISH-ARITHMETIC PROGRESSIONS-All Questions
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