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Prove that the sum of the squares of ...

Prove that the sum of the squares of the diagonals of a parallelogram is equal to the sum of the squares of its sides.

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Let, ABCD is a parallelograma
`AB = CD`, `AD = BC` [Since opposite sides of a parallelogram are equal]
AC and BD are the diagonals of the parallelogram ABCD
Draw `AE ⊥ CD`, `DF ⊥ AB`
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