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In Figure, ABD is a triangle right-angl...

In Figure, ABD is a triangle right-angled at A and `A C_|_B D`. Show that
(i)`A B^2=B C.B D`
(ii) `A C^2=B C.D C`
(iii) `A D^2=B D.C D`

Text Solution

Verified by Experts

`(##X_06_E05_03_s10##)`
(i) Here, ABD is a triangle right angled at A and `AC ⊥ BD`
`⇒ ΔBAD ∼ ΔBCA`
`⇒ (AB)/(BC) = (BD)/(AB)` (Corresponding sides of similar triangle) ...
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