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In fig., if A D|B C, prove thatA B^2+C...

In fig., if `A D_|_B C`, prove that`A B^2+C D^2=B D^2+A C^2`.

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To prove that \( AB^2 + CD^2 = BD^2 + AC^2 \) given that \( AD \perp BC \), we can follow these steps: ### Step 1: Identify the triangles We have two right triangles: \( \triangle ADC \) and \( \triangle ADB \). ### Step 2: Apply the Pythagorean theorem to triangle \( ADC \) In triangle \( ADC \): - \( AD \) is perpendicular to \( BC \). ...
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