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Sides AB and BC and median AD of a triangle ABC are respectively proportional to sides PQ and QR and median PM of `DeltaP Q R`. Show that `DeltaA B C~ DeltaP Q R`.

Text Solution

Verified by Experts

In `ΔABC` and `ΔPQR`
`(AB)/(PQ) =( BC)/(QR) = (AD)/(PM) `[given]
AD and PM are median of `ΔABC` and `ΔPQR` respectively
`⇒ (BD)/(QM )= ((BC)/2)/((QR)/2) = (BC)/(QR)`
...
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