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In figure DE || OQ and DF || OR. Show t...

In figure DE || OQ and DF || OR. Show that EF||QR.

Text Solution

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In `/_\POQ`, `DE|\|OQ`, (given)
By basic proportionality theorem, we have,
`(PE)/(EQ)= (PD)/(DO)` ...(i)
Similarly,
In `/_\POR`, `DF|\|OR`, (given)
By basic proportionality theorem, we have,
`(PD)/(DO)= (PF)/(FR)` ...(ii)
Now, from (i) and (ii),
...
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