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In Fig. 4.126, (O A)/(O C)=(O D)/(O B...

In Fig. 4.126, `(O A)/(O C)=(O D)/(O B)` . Prove that `/_A=/_C` and `/_B=/_D` . (FIGURE)

Text Solution

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Here, we are given,
`OA**OB = OC**OD`
Dividing both sides by `OB**OC`, we get,
`(OA)/(OC) = (OD)/(OB)`
Also, `/_AOD = /_BOC`
So, by Side-Angle-Side Similarity rule,
`Delta AOD~ Delta COB`
That means, `/_A=/_C and /_B =/_D`
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