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If tan(A+B)=sqrt(3)and t a n(A- B)=1/...

If `tan(A+B)=sqrt(3)`and `t a n(A- B)=1/(sqrt(3));``0^@ le A + B le 90^@` and ` A le B ,`find A and B.

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To solve the problem, we need to find the angles \( A \) and \( B \) given the equations \( \tan(A+B) = \sqrt{3} \) and \( \tan(A-B) = \frac{1}{\sqrt{3}} \), with the constraints \( 0^\circ \leq A + B \leq 90^\circ \) and \( A \leq B \). ### Step-by-Step Solution: 1. **Identify the angles from the tangent values**: - From \( \tan(A+B) = \sqrt{3} \), we know that the angle whose tangent is \( \sqrt{3} \) is \( 60^\circ \). Thus, we can write: \[ A + B = 60^\circ \quad \text{(Equation 1)} ...
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