If `sin3A=cos(A-26^@)`, where 3A is an acute angle, find the value of A.

Explanation

To solve the equation \( \sin(3A) = \cos(A - 26^\circ) \), where \( 3A \) is an acute angle, we can follow these steps:

### Step 1: Use the Complementary Angle Identity
We know that \( \sin(\theta) = \cos(90^\circ - \theta) \). Therefore, we can rewrite \( \sin(3A) \) in terms of cosine:
\[ \sin(3A) = \cos(90^\circ - 3A) \]
Now, we can set this equal to the right side of the original equation:
...