Prove the following identity, where the angles involved are acute angles for which the expressions are defined.
(iv) `(1+secA)/(secA)=(sin^2A)/(1-cosA)`

Explanation

To prove the identity \(\frac{1 + \sec A}{\sec A} = \frac{\sin^2 A}{1 - \cos A}\), we will simplify both sides step by step.

### Step 1: Simplify the Left-Hand Side (LHS)
Start with the left-hand side:
\[ \text{LHS} = \frac{1 + \sec A}{\sec A} \]
We know that \(\sec A = \frac{1}{\cos A}\). Substitute this into the expression:
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