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The decorative block shown in Fig. 13.7 ...

The decorative block shown in Fig. 13.7 is made of two solids — a cube and a hemisphere. The base of the block is a cube with edge 5 cm, and the hemisphere fixed on the top has a diameter of 4.2 cm. Find the total surface area of the block.

Text Solution

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Total Area=`6a^2`+CSA of hemisphere-Base area of hemishere)
=`6a^2+4/2pir^2=pir^2`
=`6a^2+pir^2`
=`6(5)^2+22/7(4.2/2)^2`
=`258.6 cm^2`
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