Home
Class 9
MATHS
AB is a line segment and P is its midpoi...

AB is a line segment and P is its midpoint. D and E are points on the same side of AP such that `angleBAD=angleABE and angleEPA=angleDPB`.
Show that (i) `DeltaDAP~=DeltaEBP,`
`(ii) AD=BE.`

Text Solution

Verified by Experts


i) It is given that `∠EPA = ∠DPB`
`∠EPA + ∠DPE = ∠DPB + ∠DPE` (`∠DPE` is common)
`∴ ∠DPA = ∠EPB` ...
Promotional Banner

Topper's Solved these Questions

  • TRIANGLES

    NCERT ENGLISH|Exercise Solved Examples|9 Videos
  • TRIANGLES

    NCERT ENGLISH|Exercise EXERCISE 7.5|4 Videos
  • TRIANGLES

    NCERT ENGLISH|Exercise EXERCISE 7.4|6 Videos
  • SURFACE AREAS AND VOLUMES

    NCERT ENGLISH|Exercise Exercise 13.9|3 Videos

Similar Questions

Explore conceptually related problems

In figure , D and E are Points on side BC of a Delta ABC such that BD = CE and AD = AE . Show that Delta ABD cong Delta ACE.

A B is a line segment and line l is its perpendicular bisector. If a point P lies on l , show that P is equidistant from A and Bdot

A B is a line segment and line l is its perpendicular bisector. If a point P lies on l , show that P is equidistant from A and Bdot

if D and E are points on the sides AB and AC of a DeltaABC . Such that AB=12 cm, AD=8 cm, AE=12 cm, AC= 18 cm. show that DE||BC.

A line segment AB is bisected at point P and through point P another line segment PQ, which is perpendicular to AB, is drawn. Show that : QA = QB.

AB is a line-segment. P and Q are points on opposite sides of AB such that each of them is equidistant from the points A and B. Show that the line PQ is the perpendicular bisector of AB

A B is a line segment. P\ a n d\ Q are points on opposite sides of A B such that each of them is equidistant from the points A\ a n d\ B (in figure). Show that the line P Q is perpendicular bisector of A B .

AB is a line segment and M is its mid point. Three semi circles are drawn with AM, MB and AB as diameters on the same side of the line AB. A circle with radius r unit is drawn so that it touches all thethree semi- circles. Show that AB=6xxr

DeltaA B C and DeltaD B C are two isosceles triangles on the same base BC and vertices A and D are on the same side of BC (see Fig. 7.39). If AD is extended to intersect BC at P, show that (i) \ DeltaA B D~=DeltaA C D (ii) DeltaA B P~=DeltaACP (iii) AP bisects ∠ A as well as ∠ D (iv) AP is the perpendicular bisector of BC

If D,E and F are the mid-points of the sides BC,CA and AB, respectively of a DeltaABC and O is any point, show that (i) AD+BE+CF=0 (ii) OE+OF+DO=OA