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A B is a line segment and line l is i...

`A B` is a line segment and line `l` is its perpendicular bisector. If a point `P` lines on `l ,` show that `P` is equidistant from `A\ a n d\ B`

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Line l⊥AB and passes through C which is the midpoint of AB.
To show that` PA=PB`
In `△PCA` and `△PCB`
...
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