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Show that the bisectors of angles of a ...

Show that the bisectors of angles of a parallelogram form a rectangle.

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To show that the bisectors of the angles of a parallelogram form a rectangle, we will follow these steps: ### Step 1: Define the Parallelogram Let \(ABCD\) be a parallelogram where \(A\), \(B\), \(C\), and \(D\) are the vertices. The angles at these vertices are denoted as \( \angle A\), \( \angle B\), \( \angle C\), and \( \angle D\). ### Step 2: Identify the Angle Bisectors Let the angle bisectors of \( \angle A\), \( \angle B\), \( \angle C\), and \( \angle D\) meet at points \(P\), \(Q\), \(R\), and \(S\) respectively. Thus, we have: - \(P\) is on the bisector of \( \angle A\) ...
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