Prove that the circle drawn with any sid...

Prove that the circle drawn with any side of a rhombus as a diameter, passes through the point of intersection of its diagonals.

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`ABCD` is a rhombus. Circle is drawn taking side `CD` diameter. Let the diagonals `AC` and `BD` intersect at `O`.
Angle in the semicircle and diagonals of rhombus bisect at right angles at `O`.
`/_DOC=90`
. `/_DOC=/_COB=/_BOD=/_AOD=90`
Circle passes the point of intersection of its diagonal through `O`.

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