Two chords AB and CD of lengths 5 cm and 11 cm respectively of a circle are parallel to each other and are on opposite sides of its centre. If the distance between AB and CD is 6 cm, find the radius of the circle.

Explanation

`AB=5cm` and `CD=11cm`
`OL` and `OM` are the perpendiculars on `CD` and `AB` respectively which bisect `CD` and `AB`.

Let `OL=x`, then `OM=x+3`

IN `/_\OLD`

`OD^2=OL^2+LD^2`

`OD^2=x^2+(5.5)^2`

Similarly in `/_\OMB`

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