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If circles are drawn taking two sides of a triangle as diameters, prove that the point ofintersection of these circles lie on the third side

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Two circles are drawn on the sides `AB` and `AC` of the triangle with `ABC` as diameters. The circles intersected at `D`.
`/_ADB=/_ADC=90` (Angle in the semi circle)
Now,
`/_ADB+/_ADC=180`
`/_BDC` is straight line. Thus,
Thus, `D` lies on the `BC`.
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