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The perimeter of a rectangle is 13 cm an...

The perimeter of a rectangle is 13 cm and its width is `(2) 3/4 cm .` Find its length.

A

`3 11/4`

B

`3 3/4`

C

`3 15/4`

D

`7 31/7`

Text Solution

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The correct Answer is:
To find the length of the rectangle given its perimeter and width, we can follow these steps: ### Step 1: Understand the formula for the perimeter of a rectangle. The perimeter \( P \) of a rectangle is given by the formula: \[ P = 2 \times (l + b) \] where \( l \) is the length and \( b \) is the width. ### Step 2: Identify the known values. From the problem, we know: - The perimeter \( P = 13 \) cm - The width \( b = 2 \frac{3}{4} \) cm ### Step 3: Convert the mixed number to an improper fraction. To make calculations easier, convert the width \( b \) into an improper fraction: \[ b = 2 \frac{3}{4} = \frac{2 \times 4 + 3}{4} = \frac{8 + 3}{4} = \frac{11}{4} \text{ cm} \] ### Step 4: Substitute the known values into the perimeter formula. Substituting the values of \( P \) and \( b \) into the perimeter formula: \[ 13 = 2 \times (l + \frac{11}{4}) \] ### Step 5: Simplify the equation. Distributing the 2 on the right side: \[ 13 = 2l + \frac{11}{2} \] ### Step 6: Eliminate the fraction. To eliminate the fraction, multiply both sides by 2: \[ 2 \times 13 = 2 \times (2l + \frac{11}{2}) \] \[ 26 = 4l + 11 \] ### Step 7: Solve for \( l \). Now, isolate \( l \) by first subtracting 11 from both sides: \[ 26 - 11 = 4l \] \[ 15 = 4l \] Now, divide both sides by 4: \[ l = \frac{15}{4} \text{ cm} \] ### Step 8: Convert the improper fraction back to a mixed number. To convert \( \frac{15}{4} \) into a mixed number: \[ \frac{15}{4} = 3 \frac{3}{4} \text{ cm} \] ### Final Answer: The length of the rectangle is \( 3 \frac{3}{4} \) cm. ---

To find the length of the rectangle given its perimeter and width, we can follow these steps: ### Step 1: Understand the formula for the perimeter of a rectangle. The perimeter \( P \) of a rectangle is given by the formula: \[ P = 2 \times (l + b) \] where \( l \) is the length and \( b \) is the width. ...
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