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Find the product of the following pairs ...

Find the product of the following pairs of monomials. (i) `4, 7p` (ii) `-4p, 7p` (iii) `-4p, 7pq` (iv) `4p^3, - 3p` (v) `4p,0`

Text Solution

Verified by Experts

The correct Answer is:
(i) `4xx7p = 28p`

(ii)`-4pxx7p = (-4xx7)xx(pxxp) = -28p^2`

(iii)`-4pxxx7pq = (-4xx7)xx(pxxp)xxq = -28p^2q`

(iv)`4p^3xx(-3p) = (4xx-3)xx(p^3xxp) = -12p^4`

(v)`4pxx0 = 0`
(i) `4xx7p = 28p`

(ii)`-4pxx7p = (-4xx7)xx(pxxp) = -28p^2`

(iii)`-4pxxx7pq = (-4xx7)xx(pxxp)xxq = -28p^2q`

(iv)`4p^3xx(-3p) = (4xx-3)xx(p^3xxp) = -12p^4`
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