Solve the following equations. `i)6z+10 =(-2)` `ii)` `5t+28 = 10`

Explanation

We use the concept of simple
linear equations to solve the problem.
`(a) 2y+5/2=37/2`
Transposing 5/2 to R.H.S we get,

`2y = 37/2 − 5/2`
`2y = 32/2`
`y = 16`
`(b) 5t + 28 =10`
Transposing` 28 `to R.H.S we get,
`5t = 10 − 28`
`5t = −18`
`t = −18/5`
`(c) a/5 + 3 = 2`
Transposing` 3` to R.H.S we get,
`a/5 = 2 − 3`
`a/5 = − 1`
`a = - 5v`
`(d) q/4 + 7 = 5`
Transposing `7 `to R.H.S we get,
`q/4 = 5 − 7`

`q = −8`
`(e) 5/2 x = −5`
`5x = − 5 × 2`
`5x = −10`
`x = −2`
`(f) 5/2 x = 25/4`
`5x = 25/4 × 2`
`x = 25/(2 × 5)`
`x = 5/2`
`(g) 7m + 19/2 = 13`
Transposing `19/2` to the R.H.S.
`7m = 13 − 19/2`
`7m = (26 −19)/2`
`7m = 7/2`

`m = 1/2`
`(h) 6z + 10 = −2`
Transposing `10` to the R.H.S.
`6z = −2 −10`
`z = −12/6`
`z = −2`
`(i)( 3l)/2 = 2/3`

`l = 2/3 × 2/3`
`l = 4/9`
`(j)( 2b)/3 − 5 = 3`
`(2b)/3 = 3 + 5`
`(2b)/3 = 8`
`b = 8 × 3/2`

b = 12