Home
Class 7
MATHS
Solve : (a) 3n+7=25 (b) 2p-1=23...

Solve : (a) `3n+7=25` (b) `2p-1=23`

Text Solution

Verified by Experts

`(a)` We go stepwise to separate the variable n on the `LHS` of the equation. The `LHS` is `3n + 7`. We shall first subtract `7` from it so that we get `3n`. From this, in the next step we shall divide by `3` to get n. Remember we must do the same operation on both sides of the equation. Therefore, subtracting `7` from both sides,
`3n + 7 – 7 = 25 – 7`
`3n = 18`
Now divide both sides by `3`,
`(3n)/7= 18/3`
`n=6`
`(b)` What should we do here? First we shall add `1` to both the sides:
`2p – 1 + 1 = 23 + 1`
`2p = 24`
Now divide both sides by `2`, we get `(2p)/2=24/2`
`p=12`
Promotional Banner

Topper's Solved these Questions

  • SIMPLE EQUATIONS

    NCERT ENGLISH|Exercise EXERCISE 4.3|3 Videos
  • SIMPLE EQUATIONS

    NCERT ENGLISH|Exercise EXERCISE 4.4|3 Videos
  • SIMPLE EQUATIONS

    NCERT ENGLISH|Exercise EXERCISE 4.2|4 Videos
  • RATIONAL NUMBERS

    NCERT ENGLISH|Exercise EXERCISE 9.2|4 Videos
  • SYMMETRY

    NCERT ENGLISH|Exercise EXERCISE 14.2|2 Videos

Similar Questions

Explore conceptually related problems

Solve : 7+3p=25

Solve : 3p-7=38

Solve : 1-2/3+7/3

Solve : (25)^(1/2)

Solve : 3 2/7+1/7-\ 2 3/7

Give first the step you will use to separate the variable and then solve the equation: (a) 3l = 42 (b) b/2 = 6 (c) p/7 = 4 (d) 4x = 25

Solve : 12p-5=25

The value of cot(sum_(n=1)^23 cot^-1(1+sum_(k=1)^n 2k)) is (a) 23/25 (b) 25/23 (c) 23/24 (d) 25/26

Solve for : 2/(x+1)+3/(2(x-2))=(23)/(5x);x!=0,-1,2

For all n in N, 3.5^(2n+1) + 2^(3n+1) is divisible by: (i) 17 (ii) 19 (iii) 23 (iv) 25