What should be the value of a if the value of `2x^2+x-a` equals to 5, when `x=0` ?

Options

A. -5
B. 5
C. 0
D. Not define

Explanation

To find the value of \( a \) such that the expression \( 2x^2 + x - a \) equals 5 when \( x = 0 \), we can follow these steps:

### Step 1: Substitute \( x = 0 \) into the expression
We start with the expression:
\[ 2x^2 + x - a \]
Substituting \( x = 0 \):
\[ 2(0)^2 + (0) - a \]

### Step 2: Simplify the expression
Calculating \( 2(0)^2 \) gives us 0, and \( (0) \) is also 0. Therefore, the expression simplifies to:
\[ 0 + 0 - a = -a \]

### Step 3: Set the expression equal to 5
According to the problem, this expression equals 5:
\[ -a = 5 \]

### Step 4: Solve for \( a \)
To find \( a \), we multiply both sides of the equation by -1:
\[ a = -5 \]

### Final Answer
Thus, the value of \( a \) is:
\[ \boxed{-5} \]

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