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Two trees, A and B are on the same side of a river. From a point C in the river the distance of trees A and B are 25 m and 300 m respectively. If the angle `C` is `45^0` , find the distance between the trees `(u s e\ sqrt(2)=1. 44)`

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`AB^2=CA^2+CB^2-2(CA)(CB)COS45^0`
`AB^2=250^2+300^2-2*250*300*1/sqrt2`
`AB=sqrt(250^2+300^2-sqrt2*250*300)`
`AB=215.5m`
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