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A tree stands vertically on a hill side which makes an angle of `15^0` with the horizontal. From a point on the ground 35 m down the hill from the base of three, the angle of elevation of the top of the tree is `60^0` . Find the height of the tree.

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let, `PQ` be tree and A be the point on ground AR such that `AP = 35 m`
Now `angle QAR= 60^@` and `anglePAR= 15^@`
`angle PAQ = angle QAR - anglePAR =60^@-15@=45^@`
`angleAQP= 90^@ - angleQAR =90^@-60^@ = 30^@`
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