Evaluate: `int(x+1)sqrt(2x^2+3)dx`

Explanation

Given,`x+1sqrt(2x^2+3)`

integrating the function with respect to x we get,

`int x+1sqrt(2x^2+3)dx`

=`int xsqrt(2x^2+3)dx+int 1sqrt(2x^2+3)dx`


let
`I_1=xsqrt(2x^2+3)dx`

`I_2=int 1sqrt(2x^2+3)dx`

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