Calculate the mass precent of different elements present in sodium sulphate `(Na_(2)SO_(4))`.

Explanation

The molecular foemula of sodium sulphate is ` Na_(2)SO_(4)`
Molar Mass of `Na_(2)SO_(4)= [(2xx23.0)+(32.066)+4(16.00)]`
`=142.066 g`
Mass percent of a an element ` =("mass of that element in the compound ")/( "Molar mass of the comound ")xx100`
`therefore ` Mass percent of sodium :
`= (46.0 g)/(142 .066 g) xx100`
=32.379
=32.4 %
mass percent of sulphur : ltbr gt `=(32.066 g)/(142.066 g)xx100`
=22.57
=22.6 %
Mass percent of oxygen :
`=(64.0 g)/(142.066g)xx100`
=45.049
=45.05%