Energy of an electron in the ground state of the hydrogen atom is `-2.18xx10^(-18)J`. Calculate the ionisation enthalpy of atomic hydrogen in terms of `J mol^(-1)`.
Hint: Apply the idea of mole concept to derive the answer.

Explanation

It is given that the energy of an electron in the ground state of the hydrogen atom is `-2.18 xx 10^(-18) J`.Therefore, the energy required to remove that electron from the ground state of hydrogen atom is `2.18 xx 10^(-18) J.`
`therefore` Ionization enthalpy of atomic hydrogen `= 2.18 xx 10^(-18) J`
Hence, ionization enthalpy of atomic hydrogen in terms of `J "mol"^(-1) = 2.18 xx 10^(-18) xx 6.02 xx 10^(23) J "mol"^(-1)`
`= 1.31 xx 10^(6) J "mol"^(-1)`