The value of`Delta _(f) f^(Ө)` for formation of `Cr_(2) O_(3)` is – 540 kJmol−1and that of `Al_(2) O_(3)` is `– 827 kJmol^(−1)`. Is the reduction of `Cr_(2) O_(3)` possible with Al ?

Explanation

To determine if the reduction of \( \text{Cr}_2\text{O}_3 \) is possible with aluminum (Al), we can analyze the given enthalpy of formation values for both compounds.

### Step-by-Step Solution:

1. **Identify the Given Values:**
- The enthalpy of formation for \( \text{Cr}_2\text{O}_3 \) is \( \Delta_f H^\circ = -540 \, \text{kJ/mol} \).
- The enthalpy of formation for \( \text{Al}_2\text{O}_3 \) is \( \Delta_f H^\circ = -827 \, \text{kJ/mol} \).

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