The position of and object moving along x-axis is gi en by `x=a +bt^(2)`, wher `a=8.5 m` and b=2.5 ms^(-2) and (t) is measured in ceconds. What is the velcoity `at t=1= 0`s and `t=2.0 s?` What is the average velocity between `t=2.0s` and `t=4.0 s`?

Explanation

To solve the problem step by step, we need to find the velocity at two specific times and the average velocity over a time interval.

### Step 1: Write down the position function
The position of the object is given by:
\[ x = a + bt^2 \]
where \( a = 8.5 \, \text{m} \) and \( b = 2.5 \, \text{m/s}^2 \).

### Step 2: Differentiate the position function to find velocity
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