A Saturn year is 29.5 times that earth year. How far is the Saturn from the sun if the earth is `1.50xx10^(8)` km away from the sun ?

Explanation

To find the distance of Saturn from the Sun given that a Saturn year is 29.5 times that of an Earth year, we can use Kepler's Third Law of planetary motion, which states that the square of the orbital period (T) of a planet is directly proportional to the cube of the semi-major axis (R) of its orbit.

### Step-by-Step Solution:

1. **Identify the Given Values:**
- The time period of Earth (Te) = 1 year
- The time period of Saturn (Ts) = 29.5 * Te = 29.5 years
- The distance of Earth from the Sun (Re) = 1.50 × 10^8 km
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