A geostationary satellite orbits the Earth at a height of nearly `36,000 km` from the surface of earth. What is the potential due to earth's gravity at the site of this satllite ? (Take the potential energy at infinity to be zero). Mass of the Earth `= 6.0 xx 10^(24) kg`, radius `= 6400 km, G = 6.67 xx 10^(-11) Nm^(2)//kg^(2)`.

Explanation

To find the gravitational potential due to the Earth's gravity at the site of a geostationary satellite, we can use the formula for gravitational potential \( V \):

\[ V = -\frac{GM}{R + H} \]

Where:
- \( G \) is the gravitational constant,
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