A slab of material of dielectric constant K has the same area as the plates of a parallel capacitor, but has a thickness `((3)/(4) d)`,
where d is the separation of the plates. How is the capacitance changed when the slab is inserted between the plates

Explanation

To solve the problem of how the capacitance changes when a dielectric slab is inserted between the plates of a parallel plate capacitor, we will follow these steps:

### Step-by-Step Solution:

1. **Identify the Initial Capacitance**:
The initial capacitance \( C_1 \) of a parallel plate capacitor without any dielectric is given by the formula:
\[
C_1 = \frac{\varepsilon_0 A}{d}
...