Two charged conducting spheres of radii a and b are connected to each other by a wire. What is the ratio of electric fields at the surface of two spheres ? Use the result obtained to explain why charge density on the sharp and pointed ends of a conductor is higher than on its fatter portions ?

Explanation

To solve the problem, we need to find the ratio of electric fields at the surfaces of two charged conducting spheres of radii \( a \) and \( b \) when they are connected by a wire.

### Step-by-step Solution:

1. **Understanding the Setup**:
- We have two conducting spheres with radii \( a \) and \( b \).
- When connected by a wire, both spheres will have the same electric potential \( V \).

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