Describe the change in hybridization (if any) of the `Al` atom in the following:
`AlCl_(3)+Cl^(ө)rarr AlCl_(4)^(ө)`

Explanation

To describe the change in hybridization of the aluminum (Al) atom in the reaction \( \text{AlCl}_3 + \text{Cl}^- \rightarrow \text{AlCl}_4^- \), we will follow these steps:

### Step 1: Determine the hybridization of Al in \( \text{AlCl}_3 \)

1. **Identify the number of valence electrons for Al**: Aluminum has 3 valence electrons.
2. **Count the number of monovalent atoms (Cl)**: In \( \text{AlCl}_3 \), there are 3 chlorine atoms.
3. **Determine the charge on the species**: \( \text{AlCl}_3 \) is neutral, so there is no charge to consider.
4. **Calculate the steric number using the formula**:
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