For a travelling harmonic wave `y=2.0 cos(10t-0.0080x+0.35)`, where x and y are in centimetres and t in seconds. What is the phase difference between oscillatory motion of two points separated by a distance of (a) 4m (b) 0.5 m (c ) `lambda//2` (d) `3lambda//4`

Explanation

To find the phase difference between the oscillatory motion of two points separated by a given distance for the wave described by the equation \( y = 2.0 \cos(10t - 0.0080x + 0.35) \), we will follow these steps:

### Step 1: Identify the wave parameters
The given wave equation can be compared to the standard form of a traveling wave:
\[ y = A \cos(\omega t - kx + \phi) \]
From the equation \( y = 2.0 \cos(10t - 0.0080x + 0.35) \), we can identify:
- Amplitude \( A = 2.0 \) cm
- Angular frequency \( \omega = 10 \) rad/s
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