The transvers displacement of a string (clamped at its both ends) is given by
`y(x,t) = 0.06 sin ((2pi)/(3)s) cos (120 pit)`
Where `x` and `y` are in `m` and `t` in `s`. The length of the string `1.5 m` and its mass is `3.0 xx 10^(-2) kg`.
Answer the following :
(a) Does the funcation represent a travelling wave or a stational wave ?
(b) Interpret the wave as a superposition of two waves travelling in opposite directions. What is the wavelength. Frequency and speed of each wave ?
Datermine the tension in the string.

Explanation

Let's solve the problem step by step.

### Given:
The transverse displacement of the string is given by:
\[ y(x,t) = 0.06 \sin\left(\frac{2\pi}{3} x\right) \cos(120 \pi t) \]
Where:
- \( x \) and \( y \) are in meters
- \( t \) is in seconds
...