Calculate the `pH` of `0.08` solution of `HOCI` (hydrochlorous acid). The ionisation constant of the acid is `2.5 xx 10^(-5)`. Determine the percent dissociation of `HOCI`.

Explanation

To solve the problem of calculating the pH of a 0.08 M solution of hypochlorous acid (HOCl) and determining its percent dissociation, we can follow these steps:

### Step 1: Write the dissociation equation
The dissociation of hypochlorous acid in water can be represented as:
\[ \text{HOCl} + \text{H}_2\text{O} \rightleftharpoons \text{H}_3\text{O}^+ + \text{ClO}^- \]

### Step 2: Set up the initial concentrations
Let the initial concentration of HOCl be 0.08 M. At the start, the concentrations are:
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