The photoelectric cut off voltage in a certain experiment is 1.5V. What is the maximum kinetic energy of photoelectrons emitted? `e=1.6xx10^(-19)C`.

Explanation

To find the maximum kinetic energy of the photoelectrons emitted, we can use the relationship between the cut-off voltage and the kinetic energy of the emitted electrons. The cut-off voltage (V) is given as 1.5 V, and the charge of an electron (e) is given as \(1.6 \times 10^{-19} \, C\).

### Step-by-Step Solution:

1. **Understand the relationship between cut-off voltage and kinetic energy**:
The maximum kinetic energy (K_max) of the emitted photoelectrons can be calculated using the formula:
\[
K_{\text{max}} = e \cdot V
...