The energy flux of the sunlight reaching the surface of the earth is `1.388xx10^(3) W m^(-2)`. How many photons (nearly) per square meter are incident on the earth per second? Assume that the photonsin the sunlight have an average wavelength of 550 nm.

Explanation

To solve the problem of how many photons per square meter are incident on the Earth per second, we will follow these steps:

### Step 1: Understand the Given Data
We have the following information:
- Energy flux (I) = \(1.388 \times 10^3 \, \text{W/m}^2\)
- Average wavelength of sunlight (\(\lambda\)) = \(550 \, \text{nm} = 550 \times 10^{-9} \, \text{m}\)
- Planck's constant (h) = \(6.63 \times 10^{-34} \, \text{J s}\)
- Speed of light (c) = \(3 \times 10^8 \, \text{m/s}\)
...