The work function for a certain metal is 4.2eV. Will this metal give photoelectric emission for incident radiation of wavelength 330 nm? Use, `h=6.6xx10^(-34)Js`.

Explanation

To determine whether the metal will exhibit photoelectric emission when exposed to radiation of wavelength 330 nm, we need to compare the energy of the incident photons with the work function of the metal. The work function (Φ) is given as 4.2 eV.

### Step-by-Step Solution:

1. **Convert the Wavelength to Meters**:
The wavelength (λ) is given in nanometers (nm). We need to convert it to meters (m) for our calculations.
\[
\lambda = 330 \text{ nm} = 330 \times 10^{-9} \text{ m}
...